Output Presentation

[jdhinze]

<br>
I am new to awk. Below is the awk statament I am using trying to have end result on one line for each directory.<br>
<br>
<br>
awk ' substr($0,1,1) &gt; " " { printf \ <br>
"echo -n b1/bak/%s ;ls -l /b1/bak/%s¦wc -l ;du /b1/bak/%s \n",\ <br>
$1,$1,$1,$1}' $NUM &gt; $JOB <br>
1,$1}' $NUM &gt; $JOB <br>
<br>
<br>
Output<br>
b1/bak/189 3 <br>
101588 /b1/bak/189 <br>
b1/bak/190 3 <br>
101610 /b1/bak/190 <br>
b1/bak/191 3 <br>
101590 /b1/bak/191 <br>
b1/bak/192 1 <br>
<br>
Desired Output<br>
<br>
b1/bak/189 3 101588 /b1/bak/189<br>
b1/bak/190 2 101610 /b1/bak/190<br>

 

[derekludwig]

I am not really sure what you are trying to accomplish, but the reason you have the "extra" newline is due to the 'wc'.<br>
But if what you are trying to do is list the number of entires in a directory, and then the number of blocks, I would suggest the following shell script:<br>
<br>
for dir in ${*}<br>
do<br>
print ${dir} $(find ${dir} -print ¦ wc -l) $(du ${dir})<br>
done<br>
<br>
[assuming ksh, and not really tested]<br>
<br>
If you system supports it, use 'printf' instead of 'print' to format things "better" (subjective term